Just re-checked my math. Looks like I made an algebra error.

Vf^2=Vi^2+(2)(a)(d) where Vf=velocity final, Vi=0=velocity initial, a=acceleration due to gravity, d=distance.

Vf^2=0+(2)(32ft/s^2)(230ft)

Vf^2=14720 ft^2/s^2

Vf=121 ft/sec=83 miles/hour

Regardless, everything else I stated is true. Since approx 120mph is terminal velocity for a free falling human at sea level not trying to alter his wind resistance (like a guy that just had his rope chopped), this man had not yet reached that point where his mass x gravitational acceleration equalled the opposing wind resistance vector. Hence this statement is absolutely incorrect:

"Overly simplistic although typical Physics 101 answer. Ignores (air) resistence which is related to surface area and weight."